Question

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For each item below determine the name, find it's molar mass, and it's percent composition

Answer 1

Ag2CrO4

silver chromate, 331.966 g/mol

Ag=65%, Cr=15% O=19%

CH4

Methane, 16 g/mol

C=75% H=25%

Ca3(PO4)2

calcium Phosphate, 310 g/mol

Ca=38.7% P=20% O=41.3%

C7H5N3O6

227 g/mol

C=37% H=2.2% N=18.5% O=42.3%

K2C6H5O7

BAIDAR citron, 267 g/mol

CoCl2

Cobalt (ll) Chloride, 129.93

Step-by-step explanation:

`molar \: mass = m / n \\ (m = mass \: of \: a \: substance \: in \: gram \: ) \\( n = no. \: of \: moles)`

Ag2CrO4

Ag=108, Cr=51.996, O=16

`m = (108 * 2 + 51.996 + 16 * 4)/(1) \\ = 331.966`

Ag percentage in Ag2CrO4

[(108x2)/331.966]x100

=65%

Cr percentage in Ag2CrO4

[51.966/331.966]x100

=15%

O percentage in Ag2CrO4

[(16x4)/331.966]x100

=19%

CH4

C=12 H=1

12+1x4=16 g/mol

C percentage in CH4

(12/16)x100

75%

H percentage in CH4

(4/16)x100

25%

Ca3(PO4)2

Ca=40 P=31 O=16

40x3+31x2+16x8

=310 g/mol

Ca % in Ca3(PO4)2

[(40x3) /310]x100

38.7%

P % in Ca3(PO4)2

[(31x2)/310]x100

20%

O % in Ca3(PO4)2

[(16x8)/310]x100

41.3%

C7H5N3O6

C=12 H=1 N=14 O=16

12x7+1x5+14x3+16x6

227 g/mol

C % in C7H5N3O6

[(12x7)/227]x100

37%

H % in C7H5N3O6

[(1x5)/227]x100

2.2%

N % in C7H5N3O6

[(14x3)/227]x100

18.5%

O % in C7H5N3O6

[(16x6)/227]

42.3%

• Do the same for BAIDAR cirton and Cobalt (||) Chloride
• percentage composition = [(mass of the elements x no. of elements) /molar mass of the molecule]x 100

please add this on brainleist it took me long time to write