Question

Maya is building a sandbox that is 48 inches wide. The length of the sandbox is four times the wldth of the sandbox. What is the perimeter of the sandbox?

Answer 1

the perimeter of the sandbox is 480 inches

Explanation:

The computation of the perimeter of the sandbox is shown below:

Since the width is 48 inches

And, the length would be four times the width i.e.

= 4 × 48

= 192 inches

Now the perimeter of the sandbox is

= 2( length + width)

= 2 (192 inches + 48 inches)

= 480 inches

Hence, the perimeter of the sandbox is 480 inches

Answer 2

Answer: 480 in.

Explanation:

Given

The width of the sandbox is 48 in.

The length of the sandbox is four times the width

`\therefore L=4* 48=192\ in.`

Perimeter is the sum of the sides of the shape

The perimeter of the box is

`P=2[48+192]=480\ in.`