9514 1404 393
Answer:
1. 5000
2. the year is 2003
3. > 1000; evaluate the function
Explanation:
1. The value of t is "years since 2005." In 2005, the value of t is zero. To find the model's prediction for 2005, substitute t=0.
p = 5000·2^0 = 5000·1
p = 5000 . . . . in 2005
__
2. When t=-2, it means you're concerned with the population 2 years before 2005. That is, you are modeling the population in 2003.
__
3. Evaluate the function for t=-2:
p = 5000·2^(-2) = 5000·1/4 = 1250
For t=-2, the fish population is 1250, which is more than 1000.