Question

How many g NaOH should be required to completely react 1.876 g of Copper (II) nitrate?

Molar mass of copper nitrate = 187.56 - Molar mass of NaOH = 40.0​

Answer 1

`\\ \tt\hookrightarrow 2NaOH+Cu(NO_3)_2\longrightarrow 2NaNO_3+Cu(OH)_2`

Moles of copper nitrate:-

`\\ \tt\hookrightarrow (1.876)/(187.56)=0.001mol`

• 1mol of Copper nitrate reacts with 2mol NaOH
• 0.001mol will react with 0.002mol NaOH

Madd of NaOH

`\\ \tt\hookrightarrow 0.002(40)=0.08g`