Question

A competitive cliff diver jumps into

water 81 feet below. The distance d that the diver falls
in t seconds is given by the equation d = 16t^2. How
long does it take the diver to hit the water?

Answer 1

2.25 seconds

Explanation

`d=16t^(2)`

`d=81 feet\\t=?`

Because you know what distance equals you can plug it into the equation

`81=16t^(2)`

From there you can solve by dividing the 16 over and then square rooting.

`(81)/(16)=t^(2)`

`5.0625=t^(2)`

You take the square-root to get rid of
`t^(2)`

`√(5.0625) =√(t)^(2)`

`t=2.25`