Answer:
1- there are 933.5g in 2.578 mol of C7H5BiO4
2- the molar mass of C7H5Bi04 is 362.093g
Step-by-step explanation:
To find grams you just want to convert moles into grams so:
2.578 mol • 362.093 (molar mass)
-—————- = 933.475754
1 mol
so 933.5g (for sigfigs)
finding the molar mass is actually very easy you just add up the molar mass from all the elements present in the compound (you can usually just round but for accuracy I’m using exact weights):
C - 7 (subscript) x 12.011 (molar mass) = 84.077 g
H - 5 (subscript) x 1.008 (molar mass) =
5.04 g
Bi - 1 (subscript) x 208.98 (molar mass) = 208.98 g
O - 4 (subscript) x 15.999 (molar mass) = 63.996 g
then just add them all:
84.077 g + 5.04 g + 208.98 g + 63.996 g = 362.093 g
so the molar mass of C7H5Bi04 is 362.093g
(you’ll notice that the molar mass here is the same as the one used in the equation from the first question)
hope this helps :)