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Find the area of the following figure: 11in 10in

Find the area of the following figure: 11in 10in-example-1
User AlanK
by
2.8k points

1 Answer

16 votes
16 votes

Answer:

(no simplification) = 55 + (25
\pi/2) in^2

(with simplification) = (110 + 25
\pi)/2 in^2

(with pi rounded to 3.14) = 94.25 in^2

Explanation:

Let's start with the easier shape, the triangle. The formula for area of a triangle is 1/2(base)(height). Since at the far right we have 10 in, we can apply that to the triangle to get the base = 10 inches. The height is given as 11 inches so we can then calculate the area which is 55 in^2.

Then, the circle. We know that area of a whole circle =
\pi r^(2). Since we know that a semicircle is 1/2 of a full circle, we can find the area of the entire circle then divide it by 2.

It gives the diameter as 10, divide that by 2 to get the radius. r=5. Plug 5 into the equation of
\pi r^(2) and you get 25
\pi. Divide that by 2 to get 25
\pi/2.

Add the triangle and the semicircle areas.

(no simplification) = 55 + (25
\pi/2) in^2

(with simplification) = (110 + 25
\pi)/2 in^2

(with pi rounded to 3.14) = 94.25 in^2

User Mohit Solanki
by
2.6k points