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What is the surface area of the cylinder with height 8 ft and radius 8 ft? Round your answer to the nearest thousandth.

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Final answer:

The surface area of the cylinder is approximately 803.84 square feet.

Step-by-step explanation:

To find the surface area of a cylinder, you can use the formula A = 2πrh + 2πr^2, where h is the height and r is the radius.

In this case, the height is 8 ft and the radius is 8 ft. Plugging these values into the formula, we get:

A = 2π(8 ft)(8 ft) + 2π(8 ft)^2

A = 128π ft^2 + 128π ft^2

A = 256π ft^2

Now, to round the answer to the nearest thousandth, we need to use an approximation for π. Let's use 3.1415927:

A ≈ 256(3.1415927) ft^2

A ≈ 803.84 ft^2

Therefore, the surface area of the cylinder is approximately 803.84 square feet.

User Himanshu A Jadav
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