Answer:
x = 43.4°
Explanation:
Given a triangle with two sides, say a and b and the included angle, x, the area can be directly determined using the formula
![Area = (1)/(2) \cdot a \cdot b \cdot sin(x)](https://img.qammunity.org/2023/formulas/mathematics/high-school/7nxladeycqcbpp54ynsjgjw9rdil70d5qb.png)
Here we are not given x but we can work backward since we are given area = 55, side a = 10, side b = 16
Plug in values for knowns:
![55= (1)/(2) \cdot 10 \cdot 16 \cdot sin(x)](https://img.qammunity.org/2023/formulas/mathematics/high-school/6j7ux8km2euyn9ed5kbf3v1yz7jcmdabhl.png)
55 = 80 sin(x)
Switch sides
80 sin(x) = 55
Divide both sides by 80
==> sin(x) = 55/80 = 0.6875
==> x = sin⁻¹(0.6875)
x = 43.4325°
To one decimal place this would be
x = 43.4°
Hope that helps