Question

Write and equation in slope intercept form of the line that has a slope of -6 and passes through the point (3,-4).

Answer 1

y = -6x+14

Explanation:

m = -6 ,given as x an y (3,-4)

solution y-y1 = m(x-x1)

y-(-4) = -6(x-3)

y+4 = -6x+18

then y = -6x+18-4

y = -6x+14

Answer 2

Hi! I will help you with a smile!

First of all, we have the slope of the line and a point that it passes through.

Let’s write the line’s equation in Point-Slope Form:

y-y1=m(x-x1)

Where

y1 is the y-coordinate of the point, m is the slope of the line, and x1 is the x-coordinate.

In this case, y1=-4, m=-6, and x1=3

Solve:

y-(-4)=-6(x-3)

y+4=-6x+18

y=-6x+18-4

y=-6x+14 (Answer)

Hope it helps.

Do comment if you have any query regarding my answer.

Answered by

PeacefulNature :-)