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41 votes
41 votes
Solve the equation.

{3}^(4(m + 1)) + {3}^(4m) - 246 = 0 \\


User Assael Azran
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2.5k points

2 Answers

13 votes
13 votes


3^(4m+4)+3^(4m)=246\\ (3^(4)+1)*3^(4m)=246\\82*3^(4m)=246\\3^(4m)=3\\m=(1)/(4)

User Tonto
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2.6k points
27 votes
27 votes
You group them since they have the same base (3). (3^4+1)*3^4m since they have almost the similar characters (ex. 3^4(m+1) is 3^4m+4). In the brackets we get (81+1) since 3^4 is 81, then we do the sum in the brackets (81+1) is 82 multiplied by 3^4m. Then we divide both sides with /82. 82/82 is one, 256/82 is 3. Since 3^4m and 3^1 have the same bases we just use 4m=1 where we get that m is 1/4.
Solve the equation. {3}^(4(m + 1)) + {3}^(4m) - 246 = 0 \\ ​-example-1
User Channa Ly
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2.9k points
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