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2. The density of helium is 1.78 X 104 g/cm. What is this
density in Dg/um??

User Jonathan Darryl
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1 Answer

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7 votes

Answer:


d=1.78* 10^(-7)\ Dg/\mu m^3

Step-by-step explanation:

Given,

The density of Helium is
1.78* 10^4\ g/cm^3

We need to find the density in Dg/μm

We know that,

1 g = 10 dg

1 cm³ = 10¹² μm³

So,


d=1.78 * 10^4\ g/cm^3\\\\=1.78 * 10^4* (10\ dg)/(10^(12)\ \mu m^3)\\\\=1.78* 10^(-7)\ Dg/\mu m^3

So, the density of Helium is equal to
1.78* 10^(-7)\ Dg/\mu m^3.

User Yclian
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