A 148.20 sample of an unknown substance was heated from 25°C to 40°C. In the process, the substance absorbed 5683 J of energy. What is the specific heat of the substance.

My account
Edit my Profile
Private messages
My favorites

Ask a Question
Questions
Tags
Categories
Ask a Question

Kareimovich asked Oct 15, 2022

463,603 views

3 votes

A 148.20 sample of an unknown substance was heated from 25°C to 40°C. In the process, the substance absorbed 5683 J of energy. What is the

specific heat of the substance.

Chemistry
high-school

Kareimovich asked Oct 15, 2022

by Kareimovich

2.6k points

0 Comments

Your comment on this question:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Your answer

Email me at this address if my answer is selected or commented on:Email me if my answer is selected or commented on

Privacy: Your email address will only be used for sending these notifications.

1 Answer

15 votes

Answer: 2556.455 J/(kg.°C)

Step-by-step explanation:

Im assuming the 148.20 is in grams

The equation is Q=mcΔT

Q= Heat (J)

m= Mass

c= SHC (specific heat capacity)

ΔT= Temp change

Rumel answered Oct 21, 2022

by Rumel

3.0k points

0 Comments

Your comment on this answer:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Ask a Question

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

1.6m questions

2.0m answers

0 Comments

Your comment on this question:

Your answer

1 Answer

0 Comments

Your comment on this answer:

Other Questions