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17 votes
17 votes
One hundred tickets, numbered 1, 2, 3, …, 100, are sold to 100 people for a drawing. Four different prizes are awarded, including a grand prize (a trip to Tahiti). How many ways are there to award the prizes if a) the person holding ticket 47 wins one of the prizes? b) the people holding tickets 19 and 47 both win prizes?

User Whiskey
by
2.4k points

1 Answer

17 votes
17 votes

Solution :

It is given that four different prizes were awarded. So,

a). 4 ways for person 47 to win a prize

99 ways to give out the 2nd prize

98 ways to give the 3rd prize

97 ways to give the last prize

∴ P(99,3) = 99 x 98 x 97

b). 1 way to give person 47 their prize

1 way to give person 19 their prize

98 ways to give out the 3rd prize

97 ways to give out the last prize

So, P(98,2) = 98 x 97

User Kalvin
by
2.8k points
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