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2x²+1=7x, solve the equation ​

1 Answer

3 votes

Answer:

x=(
√(41)+7)/4, (-
√(41)+7)/4

Explanation:

2x²+1=7x

2x²-7x+1=7x-7x

2x²-7x+1=0

2(x²-7x/2+1/2)=0

x²-7x/2+1/2=0

x²-7x/2+8/16=0

x²-7x/2+49/16-41/16=0

(x-7/4)^2-41/16=0

(x-7/4)^2-41/16+41/16=0+41/16

(x-7/4)^2=41/16

x-7/4=
√(41)/4 x-7/4=-
√(41)/4

x=
√(41)/4+7/4 x=-
√(41)/4+7/4

x=(
√(41)+7)/4, (-
√(41)+7)/4

User Wmacura
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