Question

Write an equation in slope-intercept form for the line that is parallel to y = 4x - 5 and contains the point (6, "-10).

Answer 1

The desired equation is y = 4x - 34

Explanation:

Start with the general slope-intercept form y = mx + b.

The new line is parallel to y = 4x - 5, and so the slope of the new line is the same as that of the old one: 4. Then we have:

y = 4x + b

Find b. Do this by substituting 6 for x and -10 for y:

-10 = 4(6) + b. Then -10 - 24 = b, and b = -34.

The desired equation is y = 4x - 34