Question

An object with a mass of 33g and a volume of 39cm^3 is placed in a liquid with a density of 1.25 g/cm^3. Find the volume of the part of the object that is NOT submerged in the liquid. Give your answer in cm^3 and with 3 significant figures.

Answer 1

V₂ = 12.6 cm³ - volume of the NOT immersed part:

Step-by-step explanation:

Given:

m = 33 g

V = 39 cm³

ρ = 1.25 g/cm³

____________

V₂ - ?

Gravity:

F = m·g

Strength of Archimedes:

Fa = ρ·g·V₁

V1 - the volume of the submerged

The object is floating, so:

F = Fa

m·g = ρ·g·V₁

m = ρ·V₁

V₁ = m / ρ = 33 / 1.25 ≈ 26,4 cm³

V₂ - volume of the NOT immersed part:

V₂ = V - V₁ = 39 - 26.4 = 12.6 cm³