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Help meeeeeeeeeeeeee pleaseeeeeeeeeee rn rnnnn!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

help meeeeeeeeeeeeee pleaseeeeeeeeeee rn rnnnn!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
help meeeeeeeeeeeeee pleaseeeeeeeeeee rn rnnnn!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Help meeeeeeeeeeeeee pleaseeeeeeeeeee rn rnnnn!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! help-example-1
User Dchest
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5.1k points

1 Answer

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Answer: \boxed {1.5}

Explanation:

The maximum height at t second after launch is the coordinate of the vertex of the parabola of the trajectory of the toy rocket

Hence,


h(t)=-16t^2+48t+3\\\\a=-16\ \ \ \ b=48\ \ \ \ c=3\\\displaystyle\\t=(-b)/(2a) \\\\t=(-48)/(2(-16)) \\\\t=(-48)/(-32) \\\\t=(3(16))/(2(16)) \\\\t=(3)/(2) \\\\t=1.5\ seconds

Help meeeeeeeeeeeeee pleaseeeeeeeeeee rn rnnnn!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! help-example-1
User Justina Chen
by
5.0k points
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