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A 0. 2 kg apple on an apple tree has a potential energy of 10 j. It falls to the ground, converting all of its pe to kinetic energy. What is the velocity of the apple just before it hits the ground?.
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A 0. 2 kg apple on an apple tree has a potential energy of 10 j. It falls to the ground, converting all of its pe to kinetic energy. What is the velocity of the apple just before it hits the ground?.

User Tharik Kanaka
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Just before the fall starts, the Apple has just potential energy which is mgh, just before hitting the ground, it has only kinetic energy which is 1/2mv^2 so 1/2mv^2=10 which leads to v=10m/s
User AlwaysQuestioning
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