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28 votes
28 votes
Divide:..........


{6a}^(3) b - 12 {a}^(4) b + 15 {a}^(3) {b}^(2) - {3a}^(2) {b}^(2) \: by \: {3a}^(2) b


User Rich Ross
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1 Answer

10 votes
10 votes

Answer:


\rm {6a}^(3) b - 12 {a}^(4) b + 15 {a}^(3) {b}^(2) - {3a}^(2) {b}^(2) \: by \: {3a}^(2) b


\rm\displaystyle(6 * a * a * a * b)/(3 * a * a * b) - (12 * a * a * a * a * b)/(3 * a * a * b) + (15 * a * a * a * b * b)/(3 * a * a * b) -(3×a×a×b×b)/(3×a×a×b)


\rm\displaystyle\frac{ \cancel6 {}^(2) * \cancel a * \cancel a * a * \cancel b}{ \cancel3 * \cancel a * \cancel a * \cancel b} - \frac{ \cancel{12 }^4* \cancel a * \cancel a * a * a * \cancel b}{ \cancel3 * \cancel a * \cancel{a }* \cancel{b}} + \frac{ \cancel{15 }{}^(3) * \cancel a * \cancel a * a * \cancel b * b}{ \cancel3 * \cancel{a} * \cancel a * \cancel b}-\frac{\cancel{3}×\cancel{a}×\cancel{a}×\cancel{b}×b}{\cancel3×\cancel{a}×\cancel{a}×\cancel{b}}


\rm2 * a - 4 * a * a \: +3 * a * \: b-b


\rm2a - 12a^3b-b

User Beactive
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