Question

Calculate the mass of NaOH required to prepare 88.25mL of 0.155M solution

Answer 1

its 0.547g

Step-by-step explanation:

for normality; we have W=(NEV)/1000

similarly for molarity; we have W= (MMwV)/1000

here the molarity is given... molecular weight of NaOH is 40 and the volume to be prepared is 88.25 ML so by formula, we have W=(0.155×40×88.25)/1000 which is equal to 0.547g. Hence, W=0.547g