Answer:
36.36 m/s
Step-by-step explanation:
From the question,
Applying the law of conservation of momentum.
Total momentum before collision = Total momentum after collision .
mu+m'u' = V(m+m')................ Equation 1
Where m = mass of the rocket, m' = mass of the wood, u = initial velocity of the rock, u' = initial velocity of the wood, V = Final velocity after collision
But, the wood was initially at rest
Therefore, u' = 0 m/s
mu = V(m+m')
make V the subject of the equation
V = mu/(m+m')................. Equation 2
Given: m = 0.5 kg, u = 400 m/s, m' = 50 kg
Substitute these values into equation 2
V = (0.5×400)/(0.5+50)
V = 200/5.5
V = 36.36 m/s