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Among 500 freshmen pursuing a business degree at a university, 311 are enrolled in an economics course, 243 are enrolled in a mathematics course, and 135 are enrolled in both an economics and a mathematics course. What is the probability that a freshman selected at random from this group is enrolled in each of the following?

a) an economics and/or a mathematics course.
b) exactly one of these two courses.
c) neither an economics course nor a mathematics course.

User Oriolpons
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1 Answer

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Solution :

Let A = Economics, B = Mathematics

n(A) = 311, n(B) = 243,
$n(A \cap B) = 135$

a). So,
$n(A \cup B) = n(A) +n(B) - n(A \cap B)$

= 311 + 243 - 135

= 419

b). n(A only) = 311 - 135

= 176

n(B only) = 243 - 135

= 108

Exactly one of these two courses


$=(176+108)/(500)$

= 0.568

c). Neither economics nor mathematics


$=(500-419)/(500) $


$=(81)/(500)$

= 0.162

User Lachanda
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