Question

If a wave has a speed of 362 m/s and a period of 4.17 ms, its wavelength is closest to

O A. 1.51 m
B.0.0115 m
OC. 86.8 m
OD. 1510 m

Answer 1

Option A (1.51 m) is the appropriate option.

Step-by-step explanation:

The given values are:

Speed of wave,

= 362 m/s

Period,

= 4.17

Now,

⇒
`v=(\lambda)/(T)`

then,

⇒
`\lambda=vT`

⇒
`= 362* 4.17* 10^(-3)`

⇒
`=1.51 \ m`