Question

A car accelerates from an initial velocity of vi=20 m/s to a final velocity of bc=35 m/s in a time interval of 5 s find avarage acceleration

Answer 1

Average acceleration of the car = 3 m/s²

Step-by-step explanation:

According to the question,

Initial velocity of the car (
`\rm v_i`) = 20 m/s

Final velocity of the car (
`\rm v_f`) = 35 m/s

Time interval of uniform acceleration (t) = 5 s

By using
`1^(st)` kinematic equation and substituting value we get:

`\rm \implies v_f = v_i + at \\ \\ \rm \implies at = v_f - v_i \\ \\ \rm \implies a = (v_f - v_i )/(t) \\ \\ \rm \implies a = (35 - 20 )/(5) \\ \\ \rm \implies a = (15)/(5) \\ \\ \rm \implies a = 3 \: m {s}^( - 2)`

`\therefore`

Average acceleration of the car is 3 m/s²