Answer:
radius = 37.69 mm
Step-by-step explanation:
Calculate the radius a of the spherical cavity that has this property
Frequency of emission = 10 GHz
This problem is similar to infinite spherical wall potential
first step:
Express the energy eigenvalue of the system :
First excited state energy can be expressed as : E
= 20.19 h^2 / 2ma^2
Given that the frequency of emission (γ ) = 10 GHz
next step :
calculate the energy of emitted photon ( E ) = h γ
= 6.626 * 10^-36 * 10 * 10^9
= 6.626 * 10^-24 joules
E
- E
= 6.626 * 10^-24
∴ a^2 = 1.42 * 10^-13 m^2
hence a = √ 1.42 * 10^-13 m^2 = 37.69 * 10^-6 m ≈ 37.69 mm