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How much potential energy is stored in a spring with a spring constant of 27 N/m if it is stretched by 16 cm
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6 votes
6 votes
How much potential energy is stored in a spring with a spring constant of 27 N/m if it is stretched by 16 cm

User Narender
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2.8k points

1 Answer

18 votes
18 votes

Answer:

PE = 0.35 J

Step-by-step explanation:

Elastic potential energy in a spring is defined by PE = (1/2)kx^2, where k is the spring constant and x is the distance compressed/stretched. Converting 16 cm to 0.16 m, we get

PE = (1/2) * 27 * (0.16^2)

PE = 0.35 J

User Doan Van Thang
by
2.7k points
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