Question

Write an equation of a parabola opens upwards and has vertex (7, - 6).


Any help?

Answer 1

f(x) = x² - 14x + 43

Explanation:

The equation of a parabola in vertex form is

f(x) = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k ) = (7, - 6 ) , then

f(x) = a(x - 7)² - 6

Since the parabola opens upwards then a > 0

let a = 1

f(x) = (x - 7)² - 6 ←in vertex form

f(x) = x² - 14x + 49 - 6

f(x) = x² - 14x + 43 ← in standard form