Question

If we add 22.5 g of HCl to 45.8 g of water, what is the percent by mass of HCl in the solution?

Answer 1

`\%m/m=33.0\%`

Step-by-step explanation:

Hello there!

In this case, since the percent by mass of a solute in a solution is computed via the following division:

`\%m/m=(m_(solute))/(m_(solute)+m_(solvent)) *100\%`

Next, given the mass of HCl and that of water, we plug them in to obtain:

`\%m/m=(22.5g)/(22.5g+45.8g) *100\%\\\\\%m/m=33.0\%`

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