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What is the vertex for the following quadratic?
f(x)= 2x^2-12x+16

What is the vertex for the following quadratic? f(x)= 2x^2-12x+16-example-1
User Mikhail Glushenkov
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3.0k points

1 Answer

30 votes
30 votes

Answer:

(3, -2)

Explanation:

To find the vertex, put the equation into vertex form by completing the square

2(x^2 - 6x) + 16 [pulling out the 2]

2(x^2 - 6x + 9) - 18 + 16 [completing the square, you subtracted 2*9 = 18 so you also add 18]

2(x - 3)^2 - 2 [simplify the equation]

vertex is (3, -2)

User Matthew Merryfull
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2.6k points