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The perimeter of the triangle is 10x^2-6x+1 and the side lengths are 5x+7 and 8x^2-4x.What is the length of the missing side?

1 Answer

4 votes

Answer:

2x^2-7x-6

Explanation:

P=A+B+C=10x^2-6x+1

A=5x+7

B=8x^2-4x

C=?

  • C=P-(A+B)

= 10x^2-6x+1-(5x+7+8x^2-4x)

=10x^2-6x+1-(8x^2-6x+7)

=2x^2-7x-6

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