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Find the surface area of the cylinder in terms of pi

Find the surface area of the cylinder in terms of pi-example-1
User Chinupson
by
2.8k points

2 Answers

23 votes
23 votes

Answer:

96π

Explanation:

SA= 2πRH+2πR^2

R=4

H=8

2π4(8)+ 2π4^2

2π32+2π16

multiply 2*32 and 2*16

64π+32π add them together

SA= 96π

User Andrey Maslov
by
2.8k points
12 votes
12 votes

Answer:

A≈301.44

Explanation:

The area of a cylinder is A=2πrh+2πr^2

You first do the first problem of the equation (A=2πrh)

You fill in the radius and height ( A=2π(4)(8) )

You first multiply 4 x 8 = 32. ( A=2π(32) )

Then you multiply 2 x 32 = 64. ( A=π(64) )

Then you multiply π x 64 (using 3.14 for π) = 200.96 m^2

You then do the second part of the equation. (A=2πr^2)

You fill in the radius. (A=2π(4)^2)

Then multiply 4 x 4 = 16 (because it's to the power of 2 [4 times itself twice]) and then multiply it by 2.

16 x 2 = 32. ( A=π(32) )

Next you just multiply 32 x π (using 3.14 for π again) = 100.48 m^2.

Then you just add them together:

200.96 m^2 + 100.48 m^2 = 301.44 m^2

So 301.44 m^2 is your answer.

(I hopefully think it is.)

User Erik Andersson
by
2.8k points
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