Question

How many mols of K+ ions in 1.75 mol of K2SO4

Answer 1

`3.5 mol K^+`

Step-by-step explanation:

Hello there!

In this case, since the mole-mole rations consider the amount of the specific ion in the whole compound, we can evidence that the potassium sulfate has two potassium ions in the molecule; in other words, there is a 1:2 mole ratio of the former to the latter; in such a way, we can perform the following proportional factor:

`1.75molK_2SO_4*(2molK^+)/(1molK_2SO_4)`

So we cancel out moles of potassium sulfate to obtain:

`3.5 mol K^+`

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