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1 vote
An electron with an initial speed of 340,000 m/s

m
/
s
is brought to rest by an electric field.

User Xahtep
by
3.2k points

1 Answer

4 votes

Answer:

0,33 Volt

Step-by-step explanation:

v = 340 000 m/s - Initial electron speed

m = 9.1·10⁻³¹ kg - Mass of an electron

W = m·v² / 2 - Initial kinetic energy of an electron

W = 9.1·10⁻³¹·(340 000)² /2 ≈ 5.26 · 10⁻²⁰ J (1)

Q = 1.6·10⁻¹⁹ C - Electron charge modulus

The work of the electric field:

A = Q·V (2)

Equate (2) and (1):

Q·V = W

V - Electric field potential difference

V = W / Q = 5.26 · 10⁻²⁰ / 1.6·10⁻¹⁹ ≈ 0,33 Volt

User KItis
by
3.4k points