Question

I have an unknown quantity of gas in 31.0 L at 260 mmHg and 87°C, how many moles of gas do I have

A 1.48 moles
B 0.36 moles
C 22.4 moles
D. 273 moles

Answer 1

Answer: B. 0.36 moles

Step-by-step explanation:

According to ideal gas equation:

`PV=nRT`

P = pressure of gas = 260 mm Hg = 0.342 atm (760 mm Hg= 1atm)

V = Volume of gas = 31.0 L

n = number of moles = ?

R = gas constant =
`0.0821Latm/Kmol`

T =temperature =
`87^0C=(87+273)K=360K`

`n=(PV)/(RT)`

`n=(0.342atm* 31.0L)/(0.0821L atm/K mol* 360K)=0.36moles`

Thus the moles of gas present are 0.36