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Passing through (3, -3) and perpendicular to y=3x+5
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Passing through (3, -3) and perpendicular to y=3x+5

User VHao
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Answer:

Find the negative reciprocal of the slope of the original line and use the point-slope formula y−y1=m(x−x1) to find the line perpendicular to y=3x−5. y=−13x−2

Explanation:

Passing through (3, -3) and perpendicular to y=3x+5-example-1
User StackOverlord
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