Question

What is the strength of the electric field of a point charge of magnitude -4.8 × 10^-19 C at a distance of 4.0 × 10^-3 m? A.-3.6 × 10^-4 N/C B.-2.7 × 10^-4 N/C C.3.6 × 10^-4 N/C D.2.7 × 10^-4 N/C

Answer 1

Given:

The point charge has a magnitude

`\begin{gathered} q=\text{ -4.8}*10^(-19)\text{ C} \\ |q|=4.8\text{ }*10^{-19\text{ }}C \end{gathered}`

The distance is

`r=\text{ 4}*10^(-3)\text{ m}`

To find the strength of the electric field.

Step-by-step explanation:

The strength of the electric field can be calculated by the formula

`E=(k|q|)/(r^2)`

Here, the constant is

`k=9*10^9\text{ Nm}^2\text{ /C}^2`

On substituting the values, the strength of the electric field will be

`\begin{gathered} E=(9*10^9*4.8*10^(-19))/((4*10^(-3))^2) \\ =\text{ 2.7}*10^(-4)\text{ N/C} \end{gathered}`