Question

Students in a statistics class took their second test. The following are the scores they earned. Create a frequency distribution and histogram for the data using a lower class limit of 49.5 and a class width of 10. Describe the shape of the distribution.b) For this one the class width is given to be the following: class width =c.)Complete the frequency/relative frequency table using the given class width. Round relative frequencies to 3 decimal places.I've screen shot the problem.

Answer 1

Part b

From the given information, we can to note that the class width is 10. The class width refers to the difference the upper and lower boundaries of any class. Therefore, the answer fo part b is. Class widh = 10

Part c

Now, lets complete the relative frequency table.

The classes are given by:

For the first class (49.5, 59.5), there are 10 numbers.

For the second class (59.5,69.5), there are 8 numbers.

For the third class (69.5,79.5), there are 4 numbers

For the fourth class (79.5,89.5) there are 2 numbers

For the fifth class (89.5,99.5) there is 1 number.

Then, the frequency column is given by:

On the other hand, the relative frequency is defined as the frequency divided by the total number of events ocurring. In our case, the total number is 10+8+4+2+1= 25. Then, the relative frequency for the first row is:

`(10)/(25)=0.4`

For the second row

`(8)/(25)=0.32`

3rd row:

`(4)/(25)=0.16`

4th row:

`(2)/(25)=0.08`

and 5th row:

`(1)/(25)=0.04`

Then, the complete table is:

Therefore, the histrogram representing this table is:

corresponding to the third option from top to bottom.

As we can note from the histogram, its shape is right skewed because has a long right tail. So, the answer for part d is: Right skewed