The line is perpendicular to the line:
![y=(1)/(5)x-1](https://img.qammunity.org/2023/formulas/mathematics/college/nnl2nl6ggdmx4yh5s7hjsjb1hfr7aoztuk.png)
so the new slope will be the inverse reciproc of the other line so the new slope will be:
![m=-5](https://img.qammunity.org/2023/formulas/mathematics/high-school/o9y8cmf6jh9smhb8sfrfqizzm5am6wl9hr.png)
now we ca unsa the formula of the slope an the coordinate (4, -2) to find the equation:
![m=(y-y_1)/(x-x_1)_{}](https://img.qammunity.org/2023/formulas/mathematics/college/6is5m0c2cgtkkwz0gctucqv1kgazgyi71f.png)
and we replase m and the coordinate so
![-5=(y-(-2))/(x-4)](https://img.qammunity.org/2023/formulas/mathematics/college/cb0olhauuactoizxy3gngn30xmvt4bkrad.png)
and we solve for y
![\begin{gathered} y+2=-5x+20 \\ y=-5x+20-2 \\ y=-5x+18 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/oz92cd5cvwtuj62689sgz74zwuip3vaybm.png)