Question

smilesSmiles| An airplane took off at a constantangle of elevation. After the plane traveledfor 26 miles, it reached an altitude of 5miles, as amodeled below. To the nearesttenth of a degree, what was the angle ofelevation ?

Answer 1

the angle of elevation is 11.1°

Step-by-step explanation:

Using an illustration to identify the position of the angle:

θ = angle of elevation

Triangle is right angled:

opposite = side opposite the angle = 5 miles

hypotenuse = 26 miles

adjacent = ?

Since we know the values of opposite and the hypotenuse, we would use sine ratio (SOH) from SOHCAHTOA

`\sin \theta=\text{ }\frac{5\text{ miles}}{26\text{ miles}}`
`\begin{gathered} \sin \theta=\text{ 0.1923} \\ \text{Inverse of sine:} \\ \theta=\sin ^(-1)(0.1923) \end{gathered}`
`\theta=\text{ 11.09}\degree`

To the enarest tenth, the angle of elevation is 11.1°