From the problem, we have an object that is composed of a cylinder and a cone.
The volume formula of a cylinder is :

and the volume formula of a cone is :

The total volume will be the sum of these volumes.

From the problem, the cylinder has a radius of r = 2 cm and the height is h1 = 7 cm.
The cone has a radius of r = 2 cm and the height is h2 = 6 cm
Using the formula above, use π = 3.

The answer is 108 cm^3
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