Simplify the sum. (8u^3+8u^2+6)+(4u^3-6u+3)

Onimusha asked Aug 15, 2022

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Onimusha asked Aug 15, 2022

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13 votes

Answer:

$\boxed{12u^3+8u^2-6u+9}$

Explanation:

(8u^3+8u^2+6)+(4u^3-6u+3) = 8u^3+8u^2+6+4u^3-6u+3

Once

$8x+4x = 12x, \text{ as } x = u^3$

$8u^3+8u^2+6+4u^3-6u+3 = 12u^3+8u^2+6-6u+3 = \boxed{12u^3+8u^2-6u+9}$

You don't need to factor.

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