Question

For the graph shown to the right, find (a) AB tó the nearest tenth and (b) the coordinates of the midpoint of AB.(a) AB=

Answer 1

`\begin{gathered} A=(-4,-4) \\ B=(6,-6) \\ \text{hence} \\ \text{distanceAB}=\sqrt[]{(-6-(-4))^2+(6-(-4))^2} \\ \text{distanceAB}=\sqrt[]{(-6+4)^2+(6+4)^2} \\ \text{distanceAB}=\sqrt[]{(-2)^2+10^2} \\ \text{distanceAB}=\sqrt[]{4+100} \\ \text{distanceAB}=\sqrt[]{104} \\ \text{distanceAB}=10.2 \end{gathered}`
`\begin{gathered} \text{midpoint M} \\ M=((6-4)/(2),(-6-4)/(2)) \\ M=((2)/(2),(-10)/(2)) \\ M=(1,-5) \end{gathered}`