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Find the distance from the point A to the given line: A(-1,7),y=3x

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Coordinates of point A = (-1,7)

if y = 3x

Then when x = 0, y = 0

when y = 0, x = 0

So the distance between two points can be found using


\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2}

so distance from A (-1, 7) and (0,0)

=> x1 = -1, y1 = 7

=> x2 = 0, y2= 0


\sqrt[]{(0_{}-7)^2+(0_{}-(-1))^2}


\begin{gathered} \sqrt[]{((7)^2+(1))^2} \\ \\ \sqrt[]{49\text{ + 1}} \\ \\ \sqrt[]{50} \\ \\ \sqrt[]{50\text{ }}\text{ = 7.07} \end{gathered}

User Iman Shafiei
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