Question

VOn October 23, 2011, one U.S. dollar was worth 49.84 Indian rupees.(a) On that date, how many rupees was 143.28 dollars worth?Round your answer to the nearest hundredth of a rupee.0₁ rupees(b) On that date, how many dollars was 129.02 rupees worth?Round your answer to the nearest hundredth of a dollar.I need help with both of these math problems

Answer 1

Step 1

Given; On October 23, 2011, one U.S. dollar was worth 49.84 Indian rupees.

(a) On that date, how many rupees was 143.28 dollars worth?

Round your answer to the nearest hundredth of a rupee.

(b) On that date, how many dollars was 129.02 rupees worth?

Round your answer to the nearest hundredth of a dollar.

Step 2

A) we use the ratio below.

`\begin{gathered} \frac{1dollar}{143.28\text{ dollars}}=\frac{49.84rupees}{x\text{ rupees}} \\ cross\text{ multiply} \end{gathered}`
`x=143.28(49.48)\approx7141\text{ rupees }`
`x=143.28(49.48)\approx7141\text{ rupees }`

B) We solve using the ratio below

`\frac{1\text{ dollar}}{x}=(49.84)/(129.02)`
`\begin{gathered} 129.02=49.84x \\ (49.84x)/(49.84)=(129.02)/(49.84) \\ x\approx\text{ \$2.59} \end{gathered}`

Answer;

`\begin{gathered} A)\text{ 7141 rupees} \\ B)\text{ \$2.59} \end{gathered}`