The free-body diagram of the configuration shown is the following:
Now, we add the forces in the vertical direction:

Since the system is in equilibrium the sum of forces in the vertical direction is zero:

Now, we add like terms:

Now, the y-component of the tension is determined using the following right triangle:
Now, we use the trigonometric function cosine:

Now, we multiply both sides by "T":

Now, we substitute in the sum of vertical forces:

Now, we solve for "T". First, we add "mg" to both sides:

Now, we divide both sides by "2cos(26.3)":

Now, we plug in the values of mass and the acceleration of gravity:

Now, we solve the operations:

Therefore, the tension is 74.88 Newton