Question

Given that T=KX/Y,find the percentage increase in T when k, xandy all increase by 20%​

Answer 1

Explanation:

Lets subsitute k, x and y as 100 to make it easier for us

So k = 100, x = 100, y = 100

Step 1 :- T = kx/y

- T = 100 * 100 / 100 = 100

Step 2 :- Increase by 20% = 100 * 20% = 20, 100 + 20 = 120

Step 3 :- Percentage Increase = Increased value OVER original calue MULTIPLIED by 100%

SO = ( 120 - 100 ) ,,,, 20/100 * 100% = 0.2* 100 = 20%

Answer 2

The percentage increase in
`T` is 20 %.

Explanation:

Let be
`T = (k\cdot x)/(y)`, whose initial parameters are
`k = k_(o)`,
`x = x_(o)` and
`y = y_(o)`. If these three parameters are increased by 20 %, then initial and final values of
`T` are, respectively:

Initial value

`T_(i) = (k_(o)\cdot x_(o))/(y_(o))` (1)

Final value

`T_(ii) = ((1.2\cdot k_(o))\cdot (1.2\cdot x_(o)))/(1.2\cdot y_(o))`

`T_(ii) = (1.2\cdot k_(o)\cdot x_(o))/(y_(o))` (2)

(1) in (2):

`T_(ii) = 1.2\cdot T_(i)`

And the percentage increase in T is:

`\%T = (T_(ii)-T_(i))/(T_(i))* 100\,\%` (3)

`\%T = (1.2\cdot T_(i)-T_(i))/(T_(i))* 100\,\%`

`\%T = 20\,\%`

The percentage increase in
`T` is 20 %.