Question

(2 to the square root of x+2) times (square root of x+3)

Answer 1

The given expression is:

`2√(x+2)*√(x+3)`

To evaluate the given expression, we apply the rule:

`\begin{gathered} √(a)*√(b)=√(ab) \\ 2=√(4) \end{gathered}`

Therefore:

`\begin{gathered} 2√(x+2)*√(x+3) \\ =√(4(x+2)(x+3)) \\ =√(4(x^2+2x+3x+6)) \\ =√(4(x^2+5x+6)) \\ =√(4x^2+20x+24) \end{gathered}`