![15^2\text{ is greater}](https://img.qammunity.org/2023/formulas/mathematics/college/t6p8gth5f7abg49ay76xfq73fi7khfu66b.png)
Here, we want to select the greater number in the pair
Generally, in cases like this, the best thing to do is to multiply out the numbers and compare the results
For the question at hand, we know quite well that 15 is greater than 13
So it is only natural that the square of 15 would be greater than the square of 13