180,994 views
36 votes
36 votes
PLEASE HELP

For the following chemical reaction, what mass of silver iodide, Agl, (in grams) will be produced from 3.11 mol of calcium
iodide, Calz?
Cal, + 2 AgNO, — 2 AgI + Ca(NO3)2

PLEASE HELP For the following chemical reaction, what mass of silver iodide, Agl, (in-example-1
User Szbalint
by
3.0k points

1 Answer

24 votes
24 votes

Answer:

1461.7 g of AgI

Step-by-step explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

CaI₂ + 2AgNO₃ —> 2AgI + Ca(NO₃)₂

From the balanced equation above,

1 mole of CaI₂ reacted to produce 2 moles of AgI.

Next, we shall determine the number of mole AgI produced by the reaction of 3.11 moles of CaI₂. This can be obtained as follow:

From the balanced equation above,

1 mole of CaI₂ reacted to produce 2 moles of AgI.

Therefore, 3.11 moles of CaI₂ will react to produce = 3.11 × 2 = 6.22 moles of AgI

Finally, we shall determine the mass of 6.22 moles of AgI. This can be obtained as follow:

Mole of AgI = 6.22 moles

Molar mass of AgI = 108 + 127

= 235 g/mol

Mass of AgI =?

Mass = mole × molar mass

Mass of AgI = 6.22 × 235

Mass of AgI = 1461.7 g

Therefore, 1461.7 g of AgI were obtained from the reaction.

User Mizhgun
by
3.0k points